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Fudgin [204]
3 years ago
15

How many atoms are in 1.75 moles of neon?

Chemistry
1 answer:
Travka [436]3 years ago
6 0

Explanation:

it contains 6.02*1023atoms

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DanielleElmas [232]
If I'm correct the answer should be a series circuit :) Hopefully this helps you out
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3 years ago
Most plants and all animals depend on _____ to meet their need for nitrogen.
kirill115 [55]
They depend on nitrogen-fixing bacteria, which convert atmospheric nitrogen into a usable form.
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3 years ago
Read 2 more answers
A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.
Anna35 [415]

Answer:

5.56 × 10⁻⁸

Explanation:

Step 1: Given data

  • Concentration of the weak acid (Ca): 0.187 M
  • pH of the solution: 3.99

Step 2: Calculate the concentration of H⁺

We will use the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3.99 = 1.02 × 10⁻⁴ M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(1.02 \times 10^{-4})^{2} }{0.187} = 5.56 \times 10^{-8}

3 0
3 years ago
If you dissolve 8.50 g of ca(no3)2 in 755 ml of distilled water what is the concentration in molarity of the calcium nitrate sol
Zanzabum
Molarity is defined as the number of moles of solute in 1 L of solution 
the mass of Ca(NO₃)₂ present - 8.50 g
therefore number of moles of Ca(NO₃)₂ - 8.50 g / 164 g/mol = 0.0518 mol
the volume of solution prepared is 755 mL 
therefore if there are 0.0518 mol in 755 mL 
then in 1000 mL the number of moles - 0.0518 mol / 0.755 L 
molarity is therefore - 0.0686 M
4 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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