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dimaraw [331]
3 years ago
6

a large aquarium has 6 more fish than a small aquarium. There are 19 fish in a large aquarium. How many fish are in a small aqua

rium
Mathematics
2 answers:
Brrunno [24]3 years ago
6 0
There are 13 fish in the small aquarium.
Firlakuza [10]3 years ago
5 0
13 fish are in the small aquarium.
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2. Choose the graph that shows the solution of the inequality on the number line
horsena [70]

Answer:

Number line 3 also known as [C]

Step-by-step explanation:

<em>Given that:</em>

<em>c ≤ </em>-1

Knowing that:

≤  = Less than or equal to

Now substitute into the equation:

C less than or equal to -1

Thus, it going left on a number line.

The only number line with left is [A] and [C]

Since ≤  = Less than or equal to -1

then, it including -1

also known as a closed circle means the number is included and an open circle means it is not.

Hence, it closed circle.

Thus, the answer is [C]

<u><em>Kavinsky</em></u>

4 0
2 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
3 years ago
Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2
Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

<u>Given quadratic equation</u>:

5x^2-6x-2=0

<u>Define the variables</u>:

  • a = 5
  • b = -6
  • c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}

\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}

\implies x=\dfrac{6 \pm \sqrt{76}}{10}

\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}

\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}

\implies x=\dfrac{6 \pm2\sqrt{19}}{10}

\implies x=\dfrac{3 \pm \sqrt{19}}{5}

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0
2 years ago
Read 2 more answers
4.289 rounded to the nearest tenth
Novay_Z [31]

Answer:

4.3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Solve for v <br> 4v=72<br> Simplify your answer as much as possible.
Ludmilka [50]
Answer:
v = 18

Explain:
Equation; 4v = 72

Begin by dividing both sides
by 4 and isolating the v
v = 18

hopefully this helps you with your problem!
(a brainliest would be appreciated)
5 0
3 years ago
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