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3 years ago

6

a large aquarium has 6 more fish than a small aquarium. There are 19 fish in a large aquarium. How many fish are in a small aqua

rium

2 answers:

Brrunno [24]3 years ago

6 0

There are 13 fish in the small aquarium.

Firlakuza [10]3 years ago

5 0

13 fish are in the small aquarium.

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The 2016 Minneapolis Resident Survey was a questionnaire that the City of Minneapolis issued to its randomly chosen residents. I

sukhopar [10]

Answer: I and III

Step-by-step explanation:

We observe in the case provided that the researcher, who has no interest in the population to intervene, is going to carry out surveys to assess whether the neighborhood is a good place to live, obtaining the following conclusions:

i. The Minneapolis Resident Survey was an observational study.

ii. The Minneapolis Resident Survey was an experiment.

iii. The figure 50.1% is a descriptive statistic for the sample.

iv. The figure 50.1% is a statistical inference for the population.:By estimating the sample, obtained by a lower percentage of the total of the respondents, it is known that with a 95% confidence interval that the rating obtained from the respondents considering that the neighborhood is a good place to live was found between 0.44 and 0.50, taking this interval as a statistical inference for the population.

The correct answer is I and III, since in this study no interventions were made to the population and only one observation of a characteristic of the neighborhood was made and in III we know that the descriptive statistic only describes data and summarizes it, which is a of the ways to display the data from the descriptive survey.

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3 years ago

How should the decimal point in 83.74 be moved to determine the product 83.74×107

monitta

Decimal point should be moved places to the right.

5 0

3 years ago

Read 2 more answers

find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

3 years ago

Math problem I need help please it will be great if you help btw don't take this question down its is a school question

Maksim231197 [3]

The first question’s answer is the last option. And the range is 104

7 0

3 years ago

Fully simplify to one fraction X/x+9 +5x+1/x

Sedaia [141]

Answer:

(5x^2+10x+1 )/x

Step-by-step explanation:

=(x/x)+9+5x+(1/x)

=(5x^2+10x+1 )/x

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4 years ago