Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
-8, -48, -288
or
-8, -4/3, -2/9
Answer:
x = 1
Step-by-step explanation:
Our goal is to isolate x on one side. So:
-6 +5x = 6x - 7
-6 = x - 7
1 = x
Hope that helped!
Answer:
Step-by-step explanation:
A
y = 7 - x
y = 7 - 2
y = 5
B
y = x^2 - 1
y = (2)^2 - 1
y = 2*2 - 1
y = 4 - 1
y = 3
C
y = x + 14
I'm going to assume that you mean (x + 14)^3
y = (x + 14)^3
y = (2 + 14)^3
y = 16^3
y = 4096
If you really do mean what it says, then
y = 2 + 14^3
y = 2744 + 2
y = 2746
