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zloy xaker [14]
3 years ago
15

Jodi has two bank accounts. Her parents started Account A for her. It currently has $100 in it, and Jodi deposits $20 into it ea

ch month. Jodi's grandparents started Account B for her. It ccurently has $300 in it, and her grandparents deposit $40 into it each month.
Account A is modeled by the function f(x)=20x+100
and Account B is modeled by the function g(x)=40x+300
, where x
represent the number of months from now.

Write a new function (f+g)(x)
that represents the total amount of money Jodi has in both accounts. Simplify your answer.
Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer: 60x+400

Step-by-step explanation:

Given

Account A can be modeled by f(x)=20x+100 and

Account B can be modeled by g(x)=40x+300

So, the function that represents the total amount of money Jodi has can be modeled by

\Rightarrow (f+g)(x)=20x+100+40x+300\\\Rightarrow (f+g)(x)=60x+400

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Answer:

1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) Solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) Solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26

So, solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: (a+b)^2=a^2+2ab+b^2

Solving:

(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: (a-b)^2=a^2-2ab+b^2

Solving:

(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

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