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MAVERICK [17]
3 years ago
7

PLEASE HELP NOWWWW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

yo is this a quiz is'int it

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Podría alguien ayudarme, es para mañana.
Ludmilka [50]

Answer:..$.$!:

Step-by-step explanation:

5 0
2 years ago
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
3 years ago
7)
Lady_Fox [76]
They pay $10.74 each
3 0
3 years ago
5x+3y-z-4x-3y-z help please ​
damaskus [11]

The simplified version of this x-2z

Step-by-step explanation:

You need to start by combining like terms. You can start with the terms that have the variable x in them. By combining those terms, the equation becomes x+3y-z-3y-z.

From here, you can combine the terms 3y and -3y, which bring the equation to x-z-z.

From here, combine the terms with the variable z. This would bring the equation down too x-2z, your final answer.

7 0
2 years ago
A car completes a journey at an average speed of 40km/h.At what speed must it travel on the return journey if the average speed
nalin [4]
The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
5 0
3 years ago
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