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hodyreva [135]
3 years ago
10

Please help as fast as you can please!

Mathematics
1 answer:
Mkey [24]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Make 4 \frac{2}{5} an improper fraction. To do that multiply the denominator, 5 by 4, which gets you 20. Then add the numerator, 2, to get 22. put the original denominator back into the fraction, and you get \frac{22}{5} . If you divide that by \frac{2}{5} , you would get 11 because you divide the numerator and the denominators cancel each other out since they are both the same number, and 22 ÷ 2 = 11.

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Marcus looked out in the audience and saw 40% of the chairs were filled. There were 42 people sitting in the chairs. Enter the t
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I say it is 16.8

Step-by-step explanation:

40 x 42

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= 16.8

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Erin wants to buy a set of paintbrushes. Store A sells a set for $25 and offers a 10% discount. Store B sells a set for $27 and
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3 years ago
A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
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Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

H_{0}: p \geq 0.16

Testing this hypothesis, means that the alternate hypothesis is:

H_{a}: p > 0.16

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that \mu = 0.16, \sigma = \sqrt{0.16*0.84}

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that n = 200, X = \frac{24}{200} = 0.12

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

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Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

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3 years ago
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