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Kobotan [32]
4 years ago
10

Im so confused at part b) is not 0.98 and i dont know what is it

Mathematics
1 answer:
Angelina_Jolie [31]4 years ago
8 0

Answer:

0.294

Step-by-step explanation:

The number of possible outcomes for 2 consecutive days is  2 (Friday, Saturday and Saturday,Sunday).

Prob( Friday, Saturday  has rain) = 0.70*0.70* 0.30) = 0.147 (No rain Sunday)

Prob( Saturday/Sunday  has rain) = 0.30*0.70*0.7) = 0.147  (No rain Friday)

Required Probability = 2*0.147

= 0.294.

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Luke bought a jacket that was 30% off the cost. He paid sales tax of 6% after the discount had been applied. If the jacket had a
nasty-shy [4]

Answer: the actual amount that Luke paid including tax is $55.65

Step-by-step explanation:

The initial price of the jacket is $75.

Luke bought a jacket that was 30% off the cost. This means that the amount of discount on the Jacket is

30/100 × 75 = 0.3 × 75 = $22.5

The price of the jacket after the discount had been applied is

75 - 22.5 = $52.5

He paid sales tax of 6% after the discount had been applied. This means that the amount of sales tax that he paid on the jacket is

6/100 × 52.5 = 0.06 × 52.5 = 3.15

Therefore, the actual amount that Luke paid including tax is

52.5 + 3.15 = $55.65

5 0
4 years ago
Ten kids can go to the water park for $95. How many can go if there is $200?
posledela

Answer:

only 2 kid's could go since the price of both is 95 for one and times it by two it's 190

5 0
3 years ago
HELP!!!!! PLEASE!!!!!!
viktelen [127]
First one hope this helps!
6 0
3 years ago
Read 2 more answers
2+2x=45<br><br> Solve for x<br><br> 10 pts
Volgvan

2+2x=45

-2

0+2x = 43

2x = 43

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3 years ago
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Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

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3 years ago
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