Question

A,E, and D are collinear. BCDE is a parallelogram. Find m

Answer 1

Answer:

B. 29º

Step-by-step explanation:

Given that BCDE is a parallelogram, then $BE \parallel CD$ and A, E and D are collinear. Then, angle E inside triangle ABE and angle D inside parallelogram BCDE have the same measure. That is:

$\angle D = \angle E = 51^{\circ}$ (1)

In addition, the sum of internal angles in triangles equals 180º, which implies that:

$\angle A + \angle B + \angle E = 180^{\circ}$ (2)

If we know that  $\angle B = 100^{\circ}$ and $\angle E = 51^{\circ}$, then $\angle A$ is:

$\angle A = 180^{\circ}-\angle B - \angle E$

$\angle A = 180^{\circ}-100^{\circ}-51^{\circ}$

$\angle A = 29^{\circ}$

Hence, correct answer is B.

Answer 2

Answer:

The answer would be be 29 degrees

Step-by-step explanation: