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2 years ago

en dos líneas paralelas cortadas por una trasversal el valor de un ángulo es 2×-14 y su suplementario mide 3×-18

Mathematics

1 answer:

ASHA 777 [7]2 years ago

3 0

Responder:

x = 42,4

Explicación paso a paso:

Podemos encontrar el valor de x ya que no se nos dice qué buscar

La suma de dos ángulos suplementarios es 180 grados, por lo tanto;

2x - 14 + 3x - 18 = 180

2x + 3x - 32 = 180

5 veces = 180 + 32

5 veces = 212

x = 212/5

x = 42,4

Por tanto, el valor de x es 42,4

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2 years ago

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

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Answer:

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Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

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Lastly, measure R' from the origin by adding the coordinates of P to R'

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2 years ago

en dos líneas paralelas cortadas por una trasversal el valor de un ángulo es 2×-14 y su suplementario mide 3×-18​

en dos líneas paralelas cortadas por una trasversal el valor de un ángulo es 2×-14 y su suplementario mide 3×-18