Question

What is the value of A when we rewrite (32/5)^-2x as A^x​

Answer 1

Answer:

$(\dfrac{25}{1024})^x$

Step-by-step explanation:

The given expression is :

$(\dfrac{32}{5})^{-2x}$

We need to rewrite it in the form of $A^x$.

We know that, $(\dfrac{1}{x})^{-a}=x^a$

So,

$(\dfrac{32}{5})^{-2x}=(\dfrac{5}{32})^{2x}\\\\=(\dfrac{5^2}{32^2})^x\\\\=(\dfrac{25}{1024})^x$

So, $A=\dfrac{25}{1024}$. Hence, this is the required solution.

Answer 2

Answer: A = (32/5)^-2

Step-by-step explanation: