Answer: D
Step-by-step explanation: I think
16= 6 ones or 16 ones
817= 8 hundreds and 7 ones or 17 ones
Hope this helps! :D
Step-by-step explanation:
multiple possibilities.
e.g.
we could use Pythagoras to get QR, and then use the law of sine to get angle P.
or we can use the law of sine to get angle R, and then use the rule that the sum of all angles in a triangle is always 180° to get angle P.
I propose the second option :
the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
with a, b, c being the sides always opposite of their associated angles.
33.8/sin(R) = 57.6/sin(90) = 57.6
sin(R) = 33.8/57.6 = 0.586805555...
R = 35.93064691...°
180 = 90 + 35.93064691... + P
P = 54.06935309...°
Answer:
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or

Step-by-step explanation:
Given
![f(x) = \sqrt[3]x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5Dx)
Required
Write a rule for g(x)
See attachment for grid
From the attachment, we have:


We can represent g(x) as:

So, we have:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
For:

![2 = n * \sqrt[3]{-1}](https://tex.z-dn.net/?f=2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D%7B-1%7D)
This gives:

Solve for n


To confirm this value of n, we make use of:

So, we have:
![-2 = n * \sqrt[3]1](https://tex.z-dn.net/?f=-2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D1)
This gives:

Solve for n


Hence:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or:

Answer:
$11
Step-by-step explanation:
Let's take 20% and convert it into a decimal, which is .20. Multiply that percentage by $55 (.20 * 55) and you get $11, which is the answer.