All categories

3 years ago

Could anyone help me with this? I will mark you as brainliest!

Mathematics

2 answers:

Likurg_2 [28]3 years ago

6 0

Answer:

0.0000016

Step-by-step explanation:

Rudiy273 years ago

6 0

(8 x 10^-3) x (2 x 10^-4)
Multiplies to (1.6 x 10^-6)
And that in standard form is 0.0000016

You might be interested in

Here are two expressions whose product is a new expression, :

Vera_Pavlovna [14]

Answer:

1. Fill in the box with 1

2. Fill in the box with -2

Step-by-step explanation:

Expression:

$(-2x^3 + [\ ]x)(x^{[\ ]}+1.5) = A$

Solving (1): Fill in the box to make it a polynomial.

To make it a polynomial, we simply fill in the box with a positive integer (say 1)

Fill in the box with 1

$(-2x^3 + [1]x)(x^{[1]}+1.5) = A$

Remove the square brackets

$(-2x^3 + x)(x^1+1.5) = A$

$(-2x^3 + x)(x+1.5) = A$

Open bracket

$-2x^4 - 3x^3 + x^2 + 1.5x = A$

Reorder

$A = -2x^4 - 3x^3 + x^2 + 1.5x$

The above expression is a polynomial.

This will work for any positive integer filled in the box

Solving (2): Fill in the box to make it not a polynomial.

The powers of a polynomial are greater than or equal to 0.

So, when the boxes are filled with a negative integer (say -2), the expression will cease to be a polynomial

Fill in the box with -2

$(-2x^3 + [-2]x)(x^{[-2]}+1.5) = A$

Remove the square brackets

$(-2x^3 - 2x)(x^{-2}+1.5) = A$

Reorder

$A = (-2x^3 - 2x)(x^{-2}+1.5)$

Open brackets

$A = -2x-3x^3-2x^{-1}-3x$

Collect Like Terms

$A = -3x^3-2x-3x-2x^{-1}$

$A = -3x^3-5x-2x^{-1}$

Notice that the least power of x is -1.

Hence, this is not a polynomial.

3 0

3 years ago

Which correctly describes the roots of the following cubic equation x^3-5x^2+3x+9=0? A. Three real roots, each with a different

77julia77 [94]

Answer:

The correct option is C.

Step-by-step explanation:

The given cubic equation is

$x^3-5x^2+3x+9=0$

According to the rational root theorem 1 and -1 are possible rational roots of all polynomial.

At x=-1, the value of function 0. Therefore (x+1) is the factor of polynomial and -1 is a real root.

Use synthetic division to find the remaining polynomial.

$(x+1)(x^2-6x+9)=0$

$(x+1)(x^2-2(3)x+3^2)=0$

Using $(a-b)^2=a^2-2ab+b^2$

$(x+1)(x-3)^2)=0$

USe zero product property and equate each factor equal to 0.

$x=-1,x=3,x=3$

Therefore the equation have three real roots out of which the value of two roots are same.

Option C is correct.

7 0

4 years ago

Read 2 more answers

Simplify: 0.6×0.2/ 0.04

Savatey [412]

Answer:

Step-by-step explanation:

4 0

3 years ago

When you use word processor functions such as spell check and thesaurus to write a second draft you are

nirvana33 [79]

C. Revising because it should be your last stage in the writing process before you publish

3 0

2 years ago

Read 2 more answers

Factor 3x^2 + 7x + 2

Dovator [93]

Answer:

(x+2)(3x+1) are the factors

3 0

3 years ago

Read 2 more answers