5 squared is the same as 5^2 which is 5*5. The answer is 25.
Answer:
$560
Step-by-step explanation:
800/10 = 80
80 x 7 = 560
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
ur answer
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Answer:
20
Step-by-step explanation:
Calculate 10% of total = 3 / 1.5 = 2
Multiply by 10x since 10% is 1/10 of 100%
2 x 10 = 20
