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Ainat [17]
3 years ago
9

Zina goes shopping. She buys in the same store two scarves and three T-shirts for

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0

Answer:

The price of T-shirts before the sale = 42 euros

The price of scarves before the sale = -77/2 euros

Step-by-step explanation:

The cost of the items Zina buys from the store initially are;

Two scarves and three T-shirts for 49 euros

The reduction in the price of scarves a week later during sales = 1.5 euros

The reduction in the price of T-shirts a week later during sales = 2 euros

The items Zina bought for 40 euros at the reduced price of the sales opportunity are;

Four scarves and five T-shirts for 40 euros

Let 'x' represent the initial price of a scarf and let 'y' represent the initial price of a T-shirt, we  have;

2·x + 3·y = 49...(1)

4·(x - 1.5) + 5·(y - 2) = 40...(2)

Expanding equation (2) gives;

4·x - 6 + 5·y - 10 = 40

4·x + 5·y = 40 + 6 + 10 = 56

∴ 4·x + 5·y = 56...(3)

By multiplying equation (1) by 2 and subtracting the result from equation (3), we get;

4·x + 5·y - 2 × (2·x + 3·y) = 56 - 2 × 49 = -63

-y = -42

y = 42

The price of T-shirts before the sale = 42 euros

x = (49 - 3 × 42)/2 = -77/2

x = -77/2

The price of scarves before the sale = -77/2 euros

(However, if the had bought the 4 scarves and 5 T-shirts during sales at 70 euros, we get;

The price of T-shirts before the sale = 12 euros

The price of scarves before the sale = 6.5 euros.

The allowable total price for the reduced 4 scarves and 5 T-shirts is between 66 and about 82 for both initial prices to be +ve)

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Answer:

less than

Step-by-step explanation:

Okay we have two polygon types here and we want to make comparison of angles.

Now for a 10-sided polygon, how do we calculate the value of each of the exterior angles?

Mathematically for any polygon , the total sum of the exterior angle is 360. Thus each in a ten sided polygon would be 360/n = 360/10 = 36

For a six sided polygon, we use the same 360/n = 360/6 = 60

So the correct answer to fill in the blank is less than

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3 years ago
The equation of a line is 4x−3y=−24.<br><br> What is the x-intercept of the line?
polet [3.4K]
To find the x int, sub in 0 for y and solve for x

4x - 3y = -24
4x - 3(0) = -24
4x = -24
x = -24/4
x = -6 <== ur x int...or (-6,0)
5 0
3 years ago
Amy needs to mail a gift card to a friend. She uses 47-cent stamps and 6-cent stamps to pay $2.42 in postage. How many of each s
AVprozaik [17]

Answer:

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

8 0
2 years ago
Read 2 more answers
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
(ab² + 13b - 4a) + (3ab² + a +7b)
Natalija [7]

Answer:

4ab² + 20b - 3a

Step-by-step explanation:

This question most likely asks us to simplify the expression, as factoring is not possible...

(ab² + 13b - 4a) + (3ab² + a + 7b),

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ab² + 3ab² + 13b + 7b - 4a + a,

Solution : 4ab² + 20b - 3a

4 0
3 years ago
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