Given:
The area model for .
To find:
The value of and the missing values in the area model.
Solution:
2.1 can be written as 2 and 0.1 on the left side of the area model.
3.2 can be written as 3 and 0.2 on the top of area model.
Area of the four parts of the area model are:
The complete area model is shown below.
After adding all areas of the area model, we get
Therefore, the value of is 6.72 and the missing values of the area model are 0.3 and 0.02 respectively.
Answer/Step-by-step explanation:
Note:
<u>Graphing From An Equation: </u>
Equation are frequently written in slope-intercept form { y = mx+b}.
Which "m" represents the slope and "b" represents the y-intercept.
<u>Solutions and Equation:</u>
Solutions to linear equations contain any points located on the graphed line.
Ordered Pair = Solution to an equation if it's values are substituted in the equation which makes it true
Solve:
{x = 0 } 3(0) - 4y = 12
-4y = 12 (0, -3 )
-4y/-4 = 12/-4
y = -3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
{y = 0} 3x-4(0) =12
3x = 12 (4,0)
3x/3 = 12/3
x = 4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
<u><em>~Lenvy~</em></u>
Answer:
B
Step-by-step explanation:
First calculate BD using sine ratio in Δ BCD and the exact value
sin60° = , thus
sin60° = =
=
=
( cross- multiply )
2BD = 12 ( divide both sides by 2 )
BD = 6
-----------------------------------------------------------
Calculate AD using the tangent ratio in Δ ABD and the exact value
tan30° = , thus
tan30° = =
=
=
( cross- multiply )
AD = 6
( divide both sides by
)
AD = 6 → B