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Svetllana [295]
3 years ago
10

My math problem is this:

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

x = 10

y = 4

Step-by-step explanation:

5x-4y=24 ------>( 1 )

-2x+7y=12 ------>( 2 )

( 1 ) × 2

(2) × 5

10x - 8y - 10x + 35y = 48 + 60

<u>27y</u><u> </u>= <u>108</u><u> </u>

27 27

y= 4

5x - 4× 4 = 24

5x - 16 = 24

x = 10

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Equivalent expression for 6(x+2)
vivado [14]

Answer:

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Step-by-step explanation:

This is an equivalent expression as all I did was simplify the expression using the distributive property. (6(x)) + (6(2)) = (6x) + (12) = 6x + 12

shown in reverse to prove this is equivalent would look like this. 6x+12 = (6(x)) + (6(2)) = 6(x+2)

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3 years ago
A bag contains 18 balls to green five black eight blue one brown one red and one white if 17 balls of a move from the bag at ran
dimaraw [331]

Answer:

P(Brown) = 0.0556 or P(Brown) = \frac{1}{18}

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Given

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Required

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P(Brown) = \frac{Brown}{Total}

Substitute values for Brown and Total

P(Brown) = \frac{1}{18}

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3 years ago
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Harlamova29_29 [7]

Answer:

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\begin{bmatrix}y+4z=-14\\ x+3z=-8\\ 2x-3y=8\end{bmatrix}\\\\Isolate\:y\:for\:y+4z =-14\: : \:y=-14-4z\\\\\mathrm{Subsititute\:}y=-14-4z\\\\\begin{bmatrix}x+3z=-8\\ 2x-3\left(-14-4z\right)=8\end{bmatrix}\\\\Isolate\:x\:for\:x+3z =-8\: :\:x =-8-3z\\\mathrm{Subsititute\:}x=-8-3z\\\\\begin{bmatrix}2\left(-8-3z\right)-3\left(-14-4z\right)=8\end{bmatrix}\\\\Simplify\\\\\begin{bmatrix}6z+26=8\end{bmatrix}\\\\Isolate\:z\:for 6z+26=8 \: ;\:z =-3\\\\\mathrm{For\:}x=-8-3z\\\\

\mathrm{Subsititute\:}z=-3\\\\x=-8-3\left(-3\right)\\\\-8-3\left(-3\right)=1\\\\x=1\\\\\mathrm{For\:}y=-14-4z\\\\\mathrm{Subsititute\:}x=1,\:z=-3\\\\y=-14-4\left(-3\right)\\\\-14-4\left(-3\right)=-2\\\\y=-2\\\\\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}\\\\y=-2,\:x=1,\:z=-3

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3 years ago
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