The answer is

first you must multiply or use the FOIL method (First, Outer, Inner, Last)
First you multiply the first terms

this gives you 3x^2, then you multiple the outer terms

this gives you -21x, then you multiply the inner terms

that gives you 2x, finally you multiply the last terms

that gives you 14, now you combine like terms

now you put all the terms together and end up with your solution
Step-by-step explanation:
y iterscept is -4 slope 2/3 rise over run
Answer:
(a) 
(b) 
<em>(b) is the same as (a)</em>
(c) 
(d) 
(e) 
Step-by-step explanation:
Given

Solving (a): Probability of 3 or fewer CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (b): Probability of at most 3 CDs
Here, we consider:

This probability is calculated as:

This gives:


<em>(b) is the same as (a)</em>
<em />
Solving (c): Probability of 5 or more CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (d): Probability of 1 or 2 CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (e): Probability of more than 2 CDs
Here, we consider:

This probability is calculated as:

This gives:


Answer:
(D.) 3x^2 + 6x
Step-by-step explanation:
the other options aren't complete and some don't even create a parabola.