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ale4655 [162]
2 years ago
6

Solve the equation below 26=8+vv=?​

Mathematics
1 answer:
faltersainse [42]2 years ago
5 0

Answer:

v=18

Step-by-step explanation:

26=8+v

8+v=26

<u>Subtract 8 from both sides:</u>

<u />8+v-8=26-8

v=18

<u>OAmalOHopeO</u>

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If AB is 8 feet, and BC is 6 feet, which is the length of AC?
Sergio039 [100]
I think it might be 10.
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3 years ago
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Choose the word that makes the sentence true. The first digit in the quotient 1,875 ÷9
motikmotik

Hi, I'm Jenny from ExperimentsDIYS and I'm here to help you with your math! :)

I am assuming that you need help with question #1 so we will proceed with that one.

Lets first divide 1,875 ÷ 9.

Using a calculator, this is equal to 208.333333333

We can simplify this number by rounding up.

208.33 would be your answer rounded.

The first digit in this quotient ( Which is the answer to a division problem) is using place value.

The decimal place value chart is attached.

The first digit will be in the hundreds place because it is on the left side of the decimal point.

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3 0
3 years ago
In this triangle, the product of sin B and tan C is<br> and the product of sin Cand tan B is
Ipatiy [6.2K]

Answer:

\frac{c}{a} and \frac{b}{a}

Step-by-step explanation:

sinB = \frac{opposite}{hypotenuse} = \frac{AC}{BC} = \frac{b}{a}

tanC = \frac{opposite}{adjacent} = \frac{AB}{AC} = \frac{c}{b}

Thus

sinB tanC = \frac{b}{a} × \frac{c}{b} ( cancel b on numerator/ denominator )

                 = \frac{c}{a}

---------------------------------------------------------------------------

sinC = \frac{opposite}{hypotenuse} = \frac{AB}{BC} = \frac{c}{a}

tanB = \frac{opposite}{adjacent} = \frac{AC}{AB} = \frac{b}{c}

Thus

sinC tanB = \frac{c}{a} × \frac{b}{c} ( cancel c on numerator/ denominator )

                 = \frac{b}{a}

7 0
2 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
2 years ago
I don’t know what it is<br> 15 ft. x 8 ft=
alexdok [17]

Answer:

The answer is 120 sq. ft.

3 0
2 years ago
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