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2 years ago

Solve the equation below 26=8+vv=?

Mathematics

1 answer:

faltersainse [42]2 years ago

5 0

Answer:

$v=18$

Step-by-step explanation:

$26=8+v$

$8+v=26$

Subtract 8 from both sides:

 $8+v-8=26-8$

$v=18$

OAmalOHopeO

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motikmotik

Hi, I'm Jenny from ExperimentsDIYS and I'm here to help you with your math! :)

I am assuming that you need help with question #1 so we will proceed with that one.

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3 years ago

In this triangle, the product of sin B and tan C is and the product of sin Cand tan B is

Ipatiy [6.2K]

Answer:

$\frac{c}{a}$ and $\frac{b}{a}$

Step-by-step explanation:

sinB = $\frac{opposite}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{b}{a}$

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---------------------------------------------------------------------------

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{c}{a}$

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Thus

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2 years ago

Find the mass of the solid paraboloid Dequals={(r,thetaθ,z): 0less than or equals≤zless than or equals≤8181minus−r2, 0less th

Lubov Fominskaja [6]

Answer:

M = 5742π

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

0 ≤ z ≤ 81 - r^2

0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

$M = \int \int \int {p ( r ,theta, z)} \, dV\\\\$

- We can write the above expression in cylindrical coordinates:

$M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\$

- Perform integration:

$M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\$

$M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] } \, dtheta\\\\M = 5742\pi kg$

- The mass evaluated is M = 5742π

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2 years ago

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Answer:

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2 years ago

Solve the equation below 26=8+vv=?​

Solve the equation below 26=8+vv=?