Answer:
$236.40
Step-by-step explanation:
Mrs. Blanda's truck holds 19.7 gallons of gas. She used 4 full tanks of gas last month.
1 full tank holds 19.7 gallons of gas
4 full tank hold 4*19.7 gallons of gas
4 full tank = 78.8 gallons of gas used last month
She paid $3 for each gallon
We need to find the amount she paid for 78.8 gallons
78.8 * 3= 236.4
Mrs. Blanda spend on gas last month = $236.40
It would be 9.13 since u would have to make it a decimal
Answer:
Stop and Save
Step-by-step explanation:
Find the cost of one apple in each place.
<u>Quick Market</u>:
Divide the total cost with the amount of apples:
1.08/3 = 0.36
The cost for one apple in <em>quick market </em>is $0.36
<u>Stop and Save</u>:
Divide the total cost with the amount of apples:
1.10/5 = 0.22
The cost for one apple in <em>Stop and Save</em> is $0.22
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$0.22 < $0.36 ∴ <em>Stop and Save</em><em> </em>is cheaper than Quickmarket by $0.14, making Stop and Save your answer.
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Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
