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Fynjy0 [20]
3 years ago
13

Need a little help here pls

Mathematics
1 answer:
Crank3 years ago
4 0

Answer:

The statements that must be true are:

XY and JK form four right angles ⇒ B

XY ⊥ JK ⇒ C

JP = KP ⇒ E

m∠JPX = 90° ⇒ F

Step-by-step explanation:

From the given figure

∵ Line XY is the perpendicular bisector of the line segment JK

→ That means line XY is the line of symmetry of the line segment JK

∴ XY ⊥ JK ⇒ C

∵ XY ∩ JK at point P

∴ P is the midpoint of JK

∵ XY ⊥ JK

∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles

∴ XY and JK form four right angles ⇒ B

∵ The measure of the right angle is 90°

∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°

∴ m∠JPX = 90° ⇒ F

∵ P is the midpoint of JK

∴ JP = KP ⇒ E

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Fynjy0 [20]
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5 0
3 years ago
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emmasim [6.3K]

Answer:

y = - 2x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

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Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

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m = \frac{2-4}{2-1} = \frac{-2}{1} = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 2 ) , then

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3 0
2 years ago
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Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

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Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

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klemol [59]

Answer:

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10y + 6° = 9(14)° - 2°

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