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3 years ago

Need a little help here pls

Mathematics

1 answer:

Crank3 years ago

4 0

Answer:

The statements that must be true are:

XY and JK form four right angles ⇒ B

XY ⊥ JK ⇒ C

JP = KP ⇒ E

m∠JPX = 90° ⇒ F

Step-by-step explanation:

From the given figure

∵ Line XY is the perpendicular bisector of the line segment JK

→ That means line XY is the line of symmetry of the line segment JK

∴ XY ⊥ JK ⇒ C

∵ XY ∩ JK at point P

∴ P is the midpoint of JK

∵ XY ⊥ JK

∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles

∴ XY and JK form four right angles ⇒ B

∵ The measure of the right angle is 90°

∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°

∴ m∠JPX = 90° ⇒ F

∵ P is the midpoint of JK

∴ JP = KP ⇒ E

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Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

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$sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}$

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