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Andreas93 [3]
3 years ago
10

Find the value of x so that the function has the given value. f(x)=8x+2;f(x)=8

Mathematics
2 answers:
sesenic [268]3 years ago
8 0
<h3>x = -\frac{1}{4}</h3><h3></h3><h3 />
Elden [556K]3 years ago
8 0
0.75 is the answer as a value
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What value of x is a solution to x3 = 216?
Ymorist [56]

Answer:

X=72

Step-by-step explanation:

216/3= 72

5 0
3 years ago
The coordinates of the vertices of a polygon are shown below. D(–4, 5), E(–1, 5), F(1, 2), and G(–1, –1) What type of polygon is
astraxan [27]

Step-by-step explanation:

Since the polygon has four vertices (D,E,F and G), it is a quadrilateral (4 vertices).

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3 years ago
Which relation is a function?<br> Can Sb help please
nikitadnepr [17]

A relation is a function if you associate exactly one output for every input. This means that, when you choose a value for x, there must be only one correspondent value for y. This only happens in the top-right parabola.

6 0
3 years ago
Write the equation of the following graph in intercept form.
Kobotan [32]

Answer:

A) f(x)=0.2(x+2)(x-5)

Step-by-step explanation:

The graph has x-intercepts at x=5 and x=-2, so our factors for the polynomial will be x+2 and x-5. This means we can rule out options B and D.

Our graph also has a y-intercept of y=-2 when x=0, so if we let f(x)=-2 and x=0, we can find the multiplier:

f(x)=a(x+2)(x-5)\\-2=a(0+2)(0-5)\\-2=a(2)(-5)\\-2=-10a\\\frac{1}{5}=a\\0.2=a

Thus, the correct equation is A) f(x)=0.2(x+2)(x-5)

8 0
2 years ago
Degree of the polynomial (2x^3)-(x^2+11) .
WARRIOR [948]

First, distribute the terms.

1(2x^3) = 2x^3

-1(x^2+11) = -x^2-11

Standard form:

2x^3 - x^2 - 11

Since there is a 3, the degree of polynomial is cubic.

8 0
3 years ago
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