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jeka57 [31]
3 years ago
7

In a class of 23 students, 9 play an instrument and 7 play a sport. There are 3

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

4/7

Step-by-step explanation:

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Ursula hiked 6 1/2 kilometers through the woods. How many decímeters did she hike ?
guajiro [1.7K]

Answer:

65,000

Step-by-step explanation:

6 1/2

= 13/2

= 6.5

6.5 * 10,000

= 65,000

3 0
3 years ago
Read 2 more answers
George ran 1000 yards in gym class. how many kilometers did he run?
Sliva [168]

He ran 7 kilometers.

5 0
3 years ago
The nutty professor sells cashews for 7.20 per pound snd brazil nuts flr 4.00 per pound. How much of each type should be used to
lutik1710 [3]

Answer:

<u>19.01 pound</u> of cashews and <u>16.99 pounds</u> of brazil nuts should be used to make a 36 pound mixture that sells for 5.69 per pound.

Step-by-step explanation:

Given:

The nutty professor sells cashews for 7.20 per pound and brazil nuts for 4.00 per pound.

Now, to find each type should be used to make a 36 pound mixture that sells for 5.69 per pound.

Let the quantity of cashews be x.

Let the quantity of brazil nuts be y.

So, total pound of mixture of nuts:

x+y=36\\y=36-x\ \ \ .....(1)

Now, the total price of mixture per pound:

7.20(x)+4.00(y)=5.69(36)

7.2x+4y=204.84

Substituting the value of y from equation (1) we get:

7.2x+4(36-x)=204.84

7.2x+144-4x=204.84

3.2x+144=204.84

Subtracting both sides by 144 we get:

3.2x=60.84

Dividing both sides by 3.2 we get:

x=19.01.

The quantity of cashews = 19.01 pound.

Now, substituting the value of x in equation (1) we get:

y=36-x\\y=36-19.01\\y=16.99.

The quantity of brazil nuts = 16.99 pounds.

Therefore, 19.01 pound of cashews and 16.99 pounds of brazil nuts should be used to make a 36 pound mixture that sells for 5.69 per pound.

7 0
4 years ago
The ratio of yellow to red flowers are 4:7 how many red flowers are there if there is 8 flowers
hram777 [196]
Ratio 4:7
If there are 8 red then number of yellow, y = 8 ×7/4=14
6 0
3 years ago
the sum of three consecutive numbers is five times the difference of the middle number and 22. find the numbers.
adelina 88 [10]

Let <em>n</em> be the smallest of the three numbers. Then

<em>n</em> + (<em>n</em> + 1) + (<em>n</em> + 2) = 5 ((<em>n</em> + 1) - 22)

Solve for <em>n</em> :

3<em>n</em> + 3 = 5 (<em>n</em> - 21)

3<em>n</em> + 3 = 5<em>n</em> - 105

2<em>n</em> = 108

<em>n</em> = 54

Then the three numbers are 54, 55, and 56.

5 0
3 years ago
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