-14.13
hopefully i’m right
9514 1404 393
Answer:
a) x≥5; y≥10; x+y≤30; 3x+y≤54
b) see attached
c) i. 14 buses; ii. 25 minibuses
Step-by-step explanation:
a. The given restrictions are ...
x ≥ 5 . . . . . . . . . minimum number of buses
y ≥ 10 . . . . . . . . minimum number of minibuses
x + y ≤ 30 . . . . .maximum number of vehicles
3x +y ≤ 54 . . . . maximum number of parking units
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b. In the attached, we have chosen to make the solution space white. The boundaries are dashed where they are included in the solution space. The vertices of the solution space are marked on the graph.
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c. The second attachment shows the maximum numbers of each.
i. maximum buses: 14 (and 12 minibuses)
ii. maximum minibuses: 25 (and 5 buses)
Lost (⬅key word) 4 is equal to -4
On 2 plays that is times 2
So all together is -4×2
A negative times a positive is negative
-4×2= -8
Hope this helped you☺
The "expected value of a ticket" is the probability of being drawn multiplied by the earnings associated to being drawn.
($1 is the price of the ticket which of course can be different).
So in this case probability is 1/2000 and the earnings would be valued $1000 (value of the plasma TV).
The expected value is 1/2000*1000=1000/2000=$0,5
This means you should not buy a $1 ticket to play except if this really brings you LOTS of amusement ;)
So the total cost depends on the price of the item(s) (c depends on p)
The independent variable is p, the price of the item, because it is not going to depend on anything else.
The dependent variable is c, because the total cost depends on how many items there are, whether your name is marked on it, etc.
The equation would be :
c = p + $3.99
I hope this was helpful!
