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10)

vaieri [72.5K]

Answer: It's supposed to be A) 13.6 ft

6 0

3 years ago

In a set of integers from 140 to 200 inclusive, how many integers are divisible by 4 and 6?

Ronch [10]

The answer to the question asked is 5.

The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are

... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5

integers divisible by 12.

_____

The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"

The number divisible by 4 is

... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16

The number divisible by 6 is

... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10

We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is

... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)

3 0

3 years ago

A simple random sample of size nequals57 is obtained from a population with muequals69 and sigmaequals2. Does the population nee

dusya [7]

Answer:

The population does not need to be normally distributed for the sampling distribution of $\bar{X}$ to be approximately normally distributed. Because of the central limit theorem. The sampling distribution of $\bar{X}$ is approximately normal.

Step-by-step explanation:

We have a random sample of size $n = 57$ from a population with $\mu = 69$ and $\sigma = 2$ . Because n is large enough (i.e., n > 30) and $\mu$ and $\sigma$ are both finite, we can apply the central limit theorem that tell us that the sampling distribution of $\bar{X}$ is approximatelly normally distributed, this independently of the distribution of the random sample. $\bar{X}$ is asymptotically normally distributed is another way to state this.

6 0

2 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

3 years ago

Which expression is equivalent to 8x+x?

mafiozo [28]

Answer:

9x

Step-by-step explanation:

You add 8x + x since they are like terms and you will get 9x.

8 0

3 years ago

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