Answer:
20ln(3)
Step-by-step explanation:
Put 15 for A and solve for t.
15 = 45e^(-.05t)
15/45 = 1/3 = e^(-.05t) . . . . divide by 45
ln(1/3) = -.05t . . . . . . . . . . . take natural logs
20ln(3) = t . . . . . . . . . . . . . . multiply by 20, simplify
It will take 20·ln(3) years for the area to decrease to 15 km^2.
Answer:
B.
Step-by-step explanation:
The answer is "C", "MW".
In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
Answer:
sorry
Step-by-step explanation:
The solution to the problem is as follows:
Just plug in the numbers and follow the pattern.
a0 = 1
a1 = 2*1 + 2 = 4
a2 = 2*4 +2 = 10
<span>a3 = 2*10 +2 = 22
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!