The answer will be d but I am not fully sure.
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
B $3,813.56 is the correct answer
1 year = $10,604
2 years = $9,331.52
3 years = $8,211.74
4 years = $7,226.33
5 years = $6,359.17
6 years = $5,596.07
7 years = $4,924.54
8 years = $4,333.60
9 years = $3,813.56
Answer:
w= -11
Step-by-step explanation:
1. Subtract 2.8 from the right side and add it to the left side. Now you have 2+6.6=1.4.
2. Subtract 2 from the left side and add it to the right side. Now you have 6.6= -.6
3. Divide both sides by -.6. You will get -11=w
