Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:
a) P(between 236 and 281 days)
b) a) P(last between 236 and 296)
c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least data lies within k standard deviation of mean.
For k = 2
Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
2(3x+7)-5(x+3)=0
6x+14-5x-15=0
x-1=0
x=1
3/4 / 5 = 3/4 / 5/1 = 3/4 * 1/5 = 3/20 of a gallon in each pitcher
I believe that Henry had $1200 dollars before.
Hope that helped!!!