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lys-0071 [83]
3 years ago
14

Examine the quadratic equation 9x^2+12x +4= 0.

Mathematics
1 answer:
mestny [16]3 years ago
4 0

Answer:

See answers and explanations

Step-by-step explanation:

A) Discriminant = b² - 4ac = (12)² - 4(9)(4) = 144 - 144 = 0

B) Since the discriminant is 0, this means the equation only has one root.

C) The root is real in this case since the discriminant is not negative. Otherwise, we would have two imaginary roots if it were (remember that complex roots come in pairs)

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Can someone please help me with this? It would be greatly appreciated:) thanks
kati45 [8]

Answer:

d < 1

Step-by-step explanation:

First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be  12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1.   Hope this helps and have a great day!!:D

3 0
3 years ago
HURRYY!
pshichka [43]
A) log (33)
B) log (7/9)

Use the log addition and subtraction rule
5 0
3 years ago
A line passes through the points (-2, 4) and (6, 16). Which of the following would not be
kvasek [131]
(4,12) is the correct answer
3 0
3 years ago
HELP!!! BRAINLIEST ANSWER!!!!
vfiekz [6]

Answer:

x = 26, y = 9

Step-by-step explanation:

Add the bottom equations and set them equal to 180

8x -28 = 180

8x = 208 divide each by 8

x = 26

Find the bottom right, 3(26) - 11

78 - 11 = 67

The unlabeled top left box is also equal to 67 degrees.

So 2y + 5 = 23

2y = 18

y = 9

7 0
3 years ago
Read 2 more answers
Where is (0,19) located? Quadrant I Quadrant II Quadrant III Quadrant IV X-axis Y-axis
12345 [234]
Let P(a, b) be a point on the coordinate plane. Then the following hold:


i) If a>0, b>0 then P is in the I.Quadrant.

ii) If a<0, b>0 then P is in the II.Quadrant.

iii) If a<0, b<0 then P is in the III.Quadrant.

iv) If a>0, b<0 then P is in the IV.Quadrant.

v) If a=0 and b is positive or negative, then P is on the y-axis.

vi) If b=0 and a is positive or negative, then P is on the x-axis.


Since we have: a=0, and 19 positive, then this point is on the y-axis.


Answer: y-axis
5 0
3 years ago
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