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3 years ago

Examine the quadratic equation 9x^2+12x +4= 0.

Mathematics

1 answer:

mestny [16]3 years ago

4 0

Answer:

See answers and explanations

Step-by-step explanation:

A) Discriminant = b² - 4ac = (12)² - 4(9)(4) = 144 - 144 = 0

B) Since the discriminant is 0, this means the equation only has one root.

C) The root is real in this case since the discriminant is not negative. Otherwise, we would have two imaginary roots if it were (remember that complex roots come in pairs)

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What is the answer to this problem above?

Ronch [10]

Answer:

Value of f (Parapedicular) = 7√6

Step-by-step explanation:

Given:

Given triangle is a right angle triangle

Value of base = 7√2

Angle made by base and hypotenuse = 60°

Find:

Value of f (Parapedicular)

Computation:

Using trigonometry application

Tanθ = Parapedicular / Base

Tan60 = Parapedicular / 7√2

√3 = Parapedicular / 7√2

Value of f (Parapedicular) = 7√2 x √3

Value of f (Parapedicular) = 7√6

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2 years ago

The scale on a map shows that 200 miles is represen by 5 inches on a map. Which proportion can be used to find the distance on t

Mandarinka [93]

Answer:

1.25 inches

Step-by-step explanation:

200 miles/ 50 miles = 5 inch / x

x = (50 x 5) / 200 = 250 / 200 = 1.25

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3 years ago

The last day we were in school was March 13. There are 180 days in a school year.

ICE Princess25 [194]

Is this qusioun as of today may 18?

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3 years ago

Sheryl's boss at always 21 pays a 5% commission on all sales. If Sheryl sells $140 worth of clothes, how much commission does sh

mariarad [96]

Answer:

She earns $7.

Step-by-step explanation:

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2 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and $a^2 = 36.$

$Then, a^2+b^2=c^2\\b^2=100-36=64$

Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

$\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1$

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3 years ago