The answer should be 12x cm power of 2
Answer:
Perimeter = 6x² + 8x
Step-by-step explanation:
Perimeter = 2(length + width)
perimeter = 2((x²+x)+(2x²+3x))
perimeter = 2(x²+2x² + x+3x)
perimeter = 2(3x² + 4x)
perimeter = 2*3x² + 2*4x
perimeter = 6x² + 8x
C because the x's repeat with the 3 and 3. If the x's repeat it is not a function.
Hope that helps.
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.