If one gallon of gasoline emits 20 pounds of CO 2 when burned in the internal combustion engine of my car, how much CO 2 does my
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Answer:
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Step-by-step explanation:
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Answer:
see explanation
Step-by-step explanation:
Using the tangent and sine ratios in the right triangle EFG
tan60° = =
=
( multiply both sides by EG )
EG × tan60° = 28 ( divide both sides by tan60° )
EG = ≈ 16.2 in ( to the nearest tenth )
--------------------------------------------------------------
sin60° = =
=
( multiply both sides by EF )
EF × sin60° = 28 ( divide both sides by sin60° )
EF = ≈ 32.3 in ( to the nearest tenth )