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lana [24]
2 years ago
15

Help, please!! I really need a correct answer, please don't answer to get points. :(

Mathematics
2 answers:
Vlad [161]2 years ago
7 0

Answer:

Multiyply all 3 numbers to get your answer.

Step-by-step explanation:

4.5*2*2

nataly862011 [7]2 years ago
7 0

Answer: 1st one is 18

second one is 44

Step-by-step explanation:

2*2*4.5=18

A=2(wl+hl+hw)=2·(2·4.5+2·4.5+2·2)=44

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Point B is the midpoint of AC, and point C is the midpoint of AD. If CD=12, what is AB?
Sliva [168]

Answer: AB = 6

Step-by-step explanation:

If CD = 12 , AC also = 12

B is the midpoint of AC so one side = 6

AB is one side of AC , so AB = 6

I am not a professional, I am simply using prior knowledge!

Note- It would mean the world to me if you would mark me brainliest!

4 0
2 years ago
Can anybody helppp meee please
crimeas [40]

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

3 0
3 years ago
---------made based on material acquisition document B. the process of determining the opportunity cost of a cost object chosen
faust18 [17]

Answer:

so its d

Step-by-step explanation:

6 0
3 years ago
A sphere with a diameter of 5 feet long is being painted. how much more paint would be needed to paint a sphere that has four ti
MArishka [77]

well, if the diameter is 5, thus its radius must be half that, or 2.5, and therefore, the radius of the one four times as much will be (4)(2.5).

Let's simply get their difference, since that'd be how much more is needed from the smaller to larger sphere.

~\hfill \stackrel{\textit{surface area of a sphere}}{SA=4\pi r^2}\qquad \qquad r=radius~\hfill \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large difference of their areas}}{\stackrel{\textit{radius of (4)(2.5)}}{4\pi (4)(2.5)^2}~~ - ~~\stackrel{\textit{radius of 2.5}}{4\pi (2.5)^2}}\implies 100\pi -25\pi \implies 75\pi ~~ \approx ~~235.62~ft^2

8 0
2 years ago
Cole jarred 8 liters of jam after 2 days. How much jam did Cole jar if he spent 5 days making jam? Assume the relationship is di
BaLLatris [955]
20 liters. If there’s 8 liters every 2 days, 8 divided by 2 is 4. 4x5 is 20 liters.
4 0
2 years ago
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