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iren [92.7K]
3 years ago
12

What is the domain of f (x) = 4 + 2x on a graph when the range is (0,6)

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

(-2, 1).

Step-by-step explanation:

When f(x) = 0

4 + 2x = 0

2x = -4

x = -2.

Ehen f(x) = 6

4 + 2x = 6

2x = 6-4 = 2

x = 1.

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John purchased 1/4 lbs of hamburger for $0.75 how much did the hamburger cost per pound
sattari [20]

there are 4 1/4 per a whole

 so multiply 0.75 x 4

0.75 x 4 = 3.00 dollars per pound

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(
SSSSS [86.1K]

Answer:

We conclude that:

\sqrt{\left(-81\right)x^2}=9ix

Step-by-step explanation:

Given the radical expression

\sqrt{\left(-81\right)x^2}

simplifying the expression

\sqrt{\left(-81\right)x^2}

Remove parentheses:  (-a) = -a

\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}

Apply radical rule:   \sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0

                 =\sqrt{-1}\sqrt{81x^2}

Apply imaginary number rule:  \sqrt{-1}=i

                 =i\sqrt{81x^2}

Apply radical rule:   \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

                  =\sqrt{81}i\sqrt{x^2}

                  =9i\sqrt{x^2}

Apply radical rule:  \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =9ix

Therefore, we conclude that:

\sqrt{\left(-81\right)x^2}=9ix

7 0
3 years ago
3) Which expression is equivalent to: 6(7-2) *<br> O 67-62<br> O42-12<br> O 7-2<br> O 13 - 8
Vlad1618 [11]

Answer:

42-12

Step-by-step explanation:

Here you go mate

Step 1

6(7-2)  Equation

Step 2

6(7-2)  simplify

6x5

answer

42-12=30  check

4 0
3 years ago
Find three consecutive even integers such that 3 times the first is 26 less than twice the sum of the last two
Dimas [21]
Let's say our first integer is "a".

how to get the next consecutive EVEN integer?  well, just add or subtract 2 from it, therefore, the second consecutive integer will be "a + 2".

and the next after that, will then be (a + 2) + 2, or "a + 4".

so those are are 3 integers, a           a + 2           a+4

notice that, from any even or odd integer, if you hop twice either forwards or backwards, you'll land on another even or odd integer respectively.

2 + 2 is 4, or 8 + 2 is 10  some even ones

3 + 2 is 5, or 13 + 2 is 15, some odd ones

\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}&#10;\\\\\\&#10;3a=2[~2a+6~]-26\implies 3a=4a+12-26\implies 3a=4a-14&#10;\\\\\\&#10;0=a-14\implies 14=a

what are the other two consecutive integers?  well, a + 2 and a + 4.
4 0
3 years ago
Multiply: 4(−5 2/3) Enter your answer as a fraction in simplest form, like this: 42/53
8_murik_8 [283]

Answer:

The amount that came is \frac{-68}{3}

Step-by-step explanation:

The computation is shown below:

According to the question, it is mentioned that

Multiply 4 by -5\frac{2}{3}

First open the equation in a fraction it would be \frac{-17}{3}

Now multiplied the above fraction by a 4

That gives the result of \frac{-68}{3}

Hence, the amount that came is \frac{-68}{3}

We simply multiply the 4 with the given fraction

Thus the above represents the simplest form of the fraction

5 0
3 years ago
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