Hypotenuse: The side of a right triangle; side from the right angle.

Mathematics

1 answer:

Stels [109]1 year ago

3 0

The Hypotenuse is the Longest side of right triangle; side Opposite from the right angle.

According to the statement

we have given that the property of the hypotenuse of the triangle and we have to complete it.

So, For this purpose, we know that the

A hypotenuse is the longest side of a right-angled triangle, and The length of the hypotenuse can be found using the Pythagorean theorem.

Now we discuss about the properties of the hypotenuse;

The hypotenuse is the longest side in a right angled triangle.
The hypotenuse is opposite the right angle.
The midpoint of the hypotenuse is the circumference.

And from these properties we have to complete the given property.

So, The Hypotenuse is the Longest side of right triangle; side Opposite from the right angle.

Learn more about hypotenuse here

brainly.com/question/3717303

#SPJ1

You might be interested in

Consider the equation

Fudgin [204]

Answer:ggx

Step-by-step explanation:

6 0

4 years ago

Super Bowl XLVI was played between the New York Giants and the New England Patriots in Indianapolis. Due to a decade-long rivalr

Diano4ka-milaya [45]

Answer:

Probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is 0.02385.

Step-by-step explanation:

We are given that Due to a decade-long rivalry between the Patriots and the city's own team, the Colts, most Indianapolis residents were rooting heartily for the Giants. Suppose that 90% of Indianapolis residents wanted the Giants to beat the Patriots.

Let p = % of Indianapolis residents wanted the Giants to beat the Patriots = 90%

The z-score probability distribution for proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = % of Indianapolis residents who were rooting for the Giants in Super Bowl XLVI in a sample of 200 residents = $\frac{170}{200}$ = 0.85

n = sample of residents = 200

So, probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is given by = P( $\hat p$ < 0.85)

P( $\hat p$ < 0.85) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.85-0.90}{\sqrt{\frac{0.85(1-0.85)}{200} } }$ ) = P(Z < -1.98) = 1 - P(Z $\leq$ 1.98)