Round the number 824,916 to the nearest tens, nearest thousands, and nearest ten-thousands.

A tree in John's backyard has been growing for 4 1/2 years. The tree is 4/5 meters tall. What is the unit rate in meters per yea

STatiana [176]

Answer:

5 127/200 meters

Step-by-step explanation:

4 1/2 = 4 5/10 | 4/5 = 8/10

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4 5/10 = 4.5 | 8/10 = 0.8

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4.8 divided by 0.8 = 5.625

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5.635 = 5 635/1000

635/1000 divided by 5 = 127/200

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5 + 127/200 = 5 127/200

4 0

3 years ago

Express 18 as a fraction of 27. Give your answer in its simplest form

den301095 [7]

Answer:

Thus, 2/3 is the simplified fraction for 18/27 by using the GCD or HCF method. Thus, 2/3 is the simplified fraction for 18/27 by using the prime factorization method

Step-by-step explanation:

hope l am not late!

6 0

3 years ago

5u^2 + 6 = -13u please help

Komok [63]

Answer:

u = -2, -3/5

General Formulas and Concepts:

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Finding roots

Step-by-step explanation:

Step 1: Define equation

5u² + 6 = -13u

Step 2: Solve for u

Rewrite: 5u² + 13u + 6 = 0
Factor: (u + 2)(5u + 3) = 0
Find roots: u = -2, -3/5

5 0

2 years ago

Lara planted some seeds. For every 3 seeds Lara planted, only 2 seeds grew.

Tresset [83]

Given:

For every 3 seeds Lara planted, only 2 seeds grew.

Altogether, 12 seeds grew.

To find:

The number of total seeds planted by Lara.

Solution:

It is given that for every 3 seeds Lara planted, only 2 seeds grew. It means the ratio of total seeds planted to seeds grew is 3:2.

Altogether, 12 seeds grew.

Let x be the number of total seeds planted by Lara. Then,

$x:12=3:2$

$\dfrac{x}{12}=\dfrac{3}{2}$

$x=\dfrac{3}{2}\times 12$

$x=18$

Therefore, the total number of seeds planter by Lara is 18.

3 0

3 years ago

Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m

strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0

3 years ago