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Anuta_ua [19.1K]
3 years ago
15

Can someone please help me asap ill mark brainlist + extra points!!!! questions 4 and 5

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0

Step-by-step explanation:

1. radius=13in

diameter= 2r =2(13)=26in

area=πr²= 22/7*(13)²

531.14in²

circumference= 2πr=2*22/7*13

81.71in

2.radius=32ft

diameter= 2r =2(32)=64ft

area=πr²= 22/7*(32)²

3218.28ft²

circumference= 2πr=2*22/7*32

201.14ft

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Ainat [17]
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3 years ago
You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

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ø=Angle theta

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1 year ago
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