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slavikrds [6]
4 years ago
10

HELLPP IDK HOW TO DOO O

Mathematics
2 answers:
Pachacha [2.7K]4 years ago
6 0

Answer: c=150-8s


Step-by-step explanation:

Given: Tyrone takes 8 pieces of candy from the bag each time he snacks. After eating 18 snacks, there are only 6 pieces of candy remaining in the bag.

The total number of candy in the bag=18\times8+6=144+6=150

Let s be the number of snacks and c be the number of candy.

The remaining candy in the bag= Total candy - candy he ate

Then the function's formula for the remaining candy is given by:-

c=150-8s

TEA [102]4 years ago
4 0

Each "snack" was 8 pieces of candy, and there were 18 of them (plus 6 candies) to start with. Hence the starting number was ...

... 18×8 +6 = 144 +6 = 150

Each snack reduced that number by 8, so the candies remaining are

... c = 150 -8s

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5 0
3 years ago
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
−5y=−5<br> 7x+6y=7<br> ​<br> Is (5,1) a solution of the system
enot [183]

Answer:no, (5,1) is not a solution for the equation. (1/7,1) will be a solution for the equation.

Step-by-step explanation:

one way to do it is to plug 1 as the y-value into the first equation which does work but when you plug 5 as the x-value and 1 as the y-value in the second equation, it will get you to 41 which does not match so it will not be an equation. the other way to check is to solve by substitution which for the first equation, you divide both side by -5 and get y=1 then substitute y with 1 in the second equation and subtract both side by 6 and get 7x=1 and divide both side by 7 to get 1/7. the y-value match but the x-value don't so (5,1) is not a solution.

8 0
3 years ago
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