Answer:
y=11
Step-by-step explanation:
Answer:
True☆The diagonals are congruent.
Not always X All sides are congruent. (Only for rectangles that are also rhombus = a square!)
Not always X The diagonals of a rectangle are perpendicular to each other. (Counterexample: draw a really long rectangle with a tiny, tiny width...the x made by the diagonals is clearly not perpendicular!)
True☆ The opposite sides are parallel. (Bc rectangles are parallelograms, part of the definition)
True☆All angles are congruent. (All four angles are right angles--part of the definition)
Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:no, (5,1) is not a solution for the equation. (1/7,1) will be a solution for the equation.
Step-by-step explanation:
one way to do it is to plug 1 as the y-value into the first equation which does work but when you plug 5 as the x-value and 1 as the y-value in the second equation, it will get you to 41 which does not match so it will not be an equation. the other way to check is to solve by substitution which for the first equation, you divide both side by -5 and get y=1 then substitute y with 1 in the second equation and subtract both side by 6 and get 7x=1 and divide both side by 7 to get 1/7. the y-value match but the x-value don't so (5,1) is not a solution.