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3 years ago

HELLPP IDK HOW TO DOO O

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

Answer: $c=150-8s$

Step-by-step explanation:

Given: Tyrone takes 8 pieces of candy from the bag each time he snacks. After eating 18 snacks, there are only 6 pieces of candy remaining in the bag.

The total number of candy in the bag= $18\times8+6=144+6=150$

Let s be the number of snacks and c be the number of candy.

The remaining candy in the bag= Total candy - candy he ate

Then the function's formula for the remaining candy is given by:-

$c=150-8s$

TEA [102]3 years ago

4 0

Each "snack" was 8 pieces of candy, and there were 18 of them (plus 6 candies) to start with. Hence the starting number was ...

... 18×8 +6 = 144 +6 = 150

Each snack reduced that number by 8, so the candies remaining are

... c = 150 -8s

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Find an equation of the circle that has center (-4, 1) and passes through (3, -5)

Lemur [1.5K]

The general equation for a circle with center (a,b) and squared radius k is

$(x-a)^2 + (y-b)^2 = k$

Here we have

$(x- - 4)^2 + (y -1)^2 = k$

and the constant is fixed by substituting in the point we know (x,y)=(3,-5)

$(x + 4)^2 + (y-1)^2 = (3+4)^2 + (-5-1)^2 = 85$

Answer:

$(x + 4)^2 + (y-1)^2 = 85$

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3 years ago

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kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

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3 years ago

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guapka [62]

Answer:

Step-by-step explanation:

3 0

3 years ago

The sides of a triangle are 1, x, and x2. what are possible values of x?

Whitepunk [10]

The sides of the triangle are given as 1, x, and x².

The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.

Consider 3 cases
Case (a): x < 1,
Then in decreasing size, the lengths are 1, x, and x².
We require that x² + x ≥ 1
Solve x² + x - 1 =
x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
Reject the negative length.
Therefore, the lengths are 0.382, 0.618 and 1.

Case (b): x = 1
This creates an equilateral triangle with equal sides
The sides are 1, 1 and 1.

Case (c): x>1
In increasing order, the lengths are 1, x, and x².
We require that x + 1 ≥ x²
Solve x² - x - 1 = 0
x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
Reject the negative answr.
The lengths are 1, 1.618 and 2.618.

Answer:
The possible lengths of the sides are
(a) 0.382, 0.618 and 1
(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.

7 0

3 years ago

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Gala2k [10]

Answer:

Step-by-step explanation:

The side to the right is 15. The side to the left is 5. You can subtract these two to find the length.

3 0

3 years ago

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