X^2 + 2x - 35
(a x b) = -35
(a + b) = 2
(7 x -5) = -35
(7 + -5) = 2
Plug them in:
x^2 - 5x + 7x -35
x(x - 5) + 7(x - 5)
Therefore, you can conclude that our final answer is...
(x + 7)(x - 5)
If you have any questions or do not understand, comment below my answer. :)
Answer:
f(x) = x² - 13x + 42
Step-by-step explanation:
given zeros are x = 6 and x = 7 then the corresponding factors are
(x - 6) and (x - 7)
the quadratic function is then the product of the factors , that is
f(x) = (x - 6)(x - 7) ← expand using FOIL
= x² - 13x + 42
That would be one I guess
Given the following function:
![\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x%5Ctext%7B%20-2%7D%7D%5Ctext%7B%20%2B%202%7D)
y = f(x)
Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,
We get,
At x = -2,
![\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20y%20%3D%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-2%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-2%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B2%5Ctext%7B%20-%202%7D%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{0}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B0%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 2 at x = -2.
At x = -3,
![\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-3%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-3%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{3-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B3-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{1}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B1%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 3 at x = -3.
At x = -6,
aight slide it here big boy
