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vekshin1
3 years ago
8

What’s the y-intercept of this line? y=x-8

Mathematics
1 answer:
Crank3 years ago
6 0

Answer:

The y-intercept of this line is -8.

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Step-by-step explanation:

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3 years ago
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Find the area of this trapezoid. Area = _______ square units. Round to the nearest whole number.
fredd [130]

Answer:

119 square units

Step-by-step explanation:

To find the area of a trapezoid, use this formula: (a+b)/2 * h

Substitute 24, 10, and 7 for a, b, and h, respectively.

((24 + 10)/2) * 7

<em>Step 1: Add 24 and 10 to get 34.</em>

(34/2) * 7

<em>Step 2: Divide 34 by 2 to get 17.</em>

17 * 7

<em>Step 3: Multiply 17 by 7 to get 119</em>

119

The area of this trapezoid is 119 square units.

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Write a unit rate for: 12 pounds for $17.88.
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4 years ago
From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle
Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ 1\text{ minute } =\frac{1}{60}\text{ degree }

20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}

50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}

By the below diagram,

tan ( 12^{\circ} 50') = \frac{8.20}{y}

tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}

tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}

\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}

Now, again by the below diagram,

tan (31^{\circ}20')=\frac{x}{y}

tan(31+\frac{1}{3})=\frac{x}{y}

\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

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3 years ago
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Click random buttons until you figure it out, or even ask a parent or teacher
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