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Lana71 [14]
3 years ago
10

Question 8 of 1010 Points

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

  • In a quadrilatteral PQRS,angle P and angle S are not opposite angles
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If 1 and -1 are the zeroes of the polynomial p(x) = ax 3 + x 2 − 2x + b, find the values of a and b
vampirchik [111]

Answer:

<h2>              a = 2,    b = -1  </h2>

Step-by-step explanation:

p(x) = ax³ + x² - 2x + b

p(1) = a(1)³ + 1² - 2•1 + b = a + 1 - 2 + b = a + b - 1

a + b - 1 = 0  ⇒   b = 1 - a

p(-1) = a(-1)³ + (-1)² - 2(-1) + b = -a + 1 + 2 + b = - a + b + 3

- a + b + 3 = 0    ∧   b = 1 - a

- a + (1 - a) + 3 = 0

- a + 1 - a + 3 = 0

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-2a = -4

 <u>a = 2</u>

<u>b = 1 - 2 = -1</u>

6 0
3 years ago
Please I'm in urgent need of help. what must be added to make (1/4)x^2-(2/3)xy a perfect square?.​
Ipatiy [6.2K]

Answer:

\bigg(\frac{2}{3}  {y} \bigg)^{2}

STEP BY STEP EXPLANATION

\frac{1}{4}  {x}^{2}  -  \bigg( \frac{2}{3}  \bigg)xy \\  \\  =   \bigg(\frac{1}{2}  {x} \bigg)^{2}  - 2. \bigg(\frac{1}{2}  {x} \bigg)\bigg( \frac{2}{3} y \bigg ) +  \bigg(\frac{2}{3}  {y} \bigg)^{2} \\  \\  = \bigg(\frac{1}{2}  {x}  -  \frac{2}{3} y\bigg)^{2}  \\

To make \red{\bold{\frac{1}{4}  {x}^{2}  -  \bigg( \frac{2}{3}  \bigg)xy}} a perfect square we should add \purple{\bold{\bigg(\frac{2}{3}  {y} \bigg)^{2}}}

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2 years ago
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Need help with this one
Tatiana [17]
Its D

i hope this helps
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3 years ago
can yall help me? 30 points to the first 2 reply with the right answer and ill make you brainist or whatever but only to one per
Finger [1]
5/6 + (-4/6)

1/6

gehshswjbwvwvwgwgwuwhwbssbs
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2 years ago
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Help please, there is a big prize up for grabs
zmey [24]
1: a) -51

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