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Morgarella [4.7K]
3 years ago
10

Which expression is equivalent to b^-2/ab^-5?a) a/b^5b)1/ab^5c)a^3b/1d)b/a

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{-n}}\implies a^{{ n}}\\\\
-------------------------------\\\\
\cfrac{b^{-2}}{ab^{-5}}\implies \cfrac{b^{-2}\cdot b^{+5}}{a}\implies \cfrac{b^{-2+5}}{a}\implies \cfrac{b^3}{a}
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I need help is it A B C or D
SVEN [57.7K]
The answer is D hope this helps :]
4 0
3 years ago
A bag contains yellow marbles and blue marbles, 73 in total. The number of yellow marbles is 7 more than 5 times the number of b
Roman55 [17]

Answer:

number of yellow marbles=62.

Step-by-step explanation:

It is given that in a bag there are yellow marbles and blue marbles and the total number of marbles=73.

Let the number of Blue marbles=x, then according to the question, number of yellow marbles will be =5x+7.

Now, Total number of marbles= number of yellow marbles+number of blue marbles.

⇒73=x+5x+7

⇒73-7=6x

⇒66=6x

⇒x=11

Therefore, numberof blue marbles=x=11 and

number of yellow marbles=5x+7=5(11)+7=55+7=62.

8 0
3 years ago
Select the step in the solution that shows the first error.
siniylev [52]

Answer:

Step 2: 20x = 80 + 10x

Step-by-step explanation:

Step 1: 20x - 10 = 80 + 10x

Add 10 to each side

20x - 10+10 = 80+10 + 10x

20x  = 90 + 10x

Step 2: 20x = 80 + 10x   This has the first error

Step 3: 10x = 80

Step 4: x= 8

8 0
3 years ago
Which of the following sets is not finite?
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\{x|x\in\mathbb{N}\ \wedge\ n < 10\}=\{0;\ 1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9\}-FINITE\\\\\{x|x\in\mathbb{Z}\ \wedge\ 0 < x < 10\}=\{1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9\}-FINITE\\\\\{x|x\in\mathbb{Z}\ \wedge\ x < 0\}=\{...;-4;-3;-2;-1\}=\mathbb{Z}^--NOT\ FINITE
8 0
3 years ago
Please Answers with steps...will be much appreciated!!!
11Alexandr11 [23.1K]
To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:

 7) (x)=x³-6x²+8x
 (x)=x(x³-6x²+8)
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 The lenght is: x
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 8) √(2x+8)-6=4

1. You need to clear the variable "x". Then:

 √(2x+8)=4+6
 √(2x+8)=10
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 2x+8=100
 2x=100-8
 x=92/2
 x=46

 9) l4x+3l=9+2x

 1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:

 2. Negative:

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 2x=6
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4 0
2 years ago
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