You need two terms that multiply to (12x-4). The term on the outside needs to be a common multiple of 12 and 4. The common factors are 1, 2, and 4. Here are the following possible dimensions:
1(12x-4)
2(6x-2)
4(3x-1)
Hope this helps.
The answer is <em>x</em>=5.
Solve for <em>x</em>. (The question mark should be <em>x</em>.)
Answer:
Options (1), (3) and (5)
Step-by-step explanation:
Equation that represents the relationship between the three sides of a triangle is,
a² + b² = c²
Where c = longest side of the triangle
If the length of the given sides satisfy the equation, triangle formed by the sides will be a right triangle.
Option A.
27 in, 36 in, 45 in
(45)² = (27)² + (36)²
2025 = 729 + 1296
2025 = 2025
True.
Option 2.
18 in, 22 in, 28 in
(28)² = (18)² + (22)²
784 = 324 + 484
784 = 808
False.
Option 3
10 in, 24 in, 26 in
(26)² = (10)² + (24)²
676 = 100 + 576
676 = 676
True.
Option 4
20 in, 21 in, 31 in
(31)² = (20)² + (21)²
961 = 400 + 441
961 = 841
False.
Option 5
28 in, 45 in, 53 in
(53)² = (28)² + (45)²
2809 = 784 + 2025
2809 = 2809
True.
Therefore, Options (1), (3) and (5) will be the correct options.
Answer:
(a)
x cubed is
=x^3=x3
5 times the cube of x is
=5x^3=5x3
4 times x is
=4x=4x
the quotient of 4 times x and 3 is
=\frac{4x}{3}=34x
so,
the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is
=5x^3-\frac{4x}{3}=5x3−34x ..........Answer
(b)
5 times cube of x is
=5x^3=5x3
5 times cube of x divided by 4 times x is
=\frac{5x^3}{4x}=4x5x3 ..........Answer
(c)
difference of 5 times x cube and 4 is
=5x^3 -4=5x3−4
so,
the quotient of the difference of 5 times x cube and 4 and x is
=\frac{5x^3-4}{x}=x5x3−4 ...........Answer
(d)
difference of 5 times x and 4 is
=5x-4=5x−4
so,
the cube of the difference of 5 times x and 4 is is
=(5x-4)^3=(5x−4)3 ............Answer
