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Olin [163]
3 years ago
5

NEED HELP ON THIS ASAP

Mathematics
1 answer:
mihalych1998 [28]3 years ago
3 0

Answer:

its 12 i think because if A D is 5 E B looks about double that so i think its 12

Step-by-step explanation:

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Quadratic equations Please Help Me!!!!!!
igor_vitrenko [27]

The roots are 1 +√7 and 1 -√7.

<h3>What is Quadratic equation?</h3>

A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0

Given equation:

y= x²+2x-6

First,

Half the coefficient of x and add and subtract the square of (b/2)

y= x²+2x-6+(1)²-(1)²

y= x²+2x+(1)² -6 -(1)²

y= (x+1)² -7

Now, equate y=0

(x+1)² -7 =0

(x+1)² = 7

x+1= ±√7

x=1 ±√7

Hence, the roots are 1 +√7 and 1 -√7.

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7 0
1 year ago
What is y=3/8x-5<br> in a table of values
iogann1982 [59]
It is 8x-5 you replace the variable y with 3 in the expression
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6 0
3 years ago
Hey guys!! Kon'nichiwa!!
mina [271]

Answer:

1. 1.79

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2 years ago
Read 2 more answers
Step 2 - Fill in the missing number: A vertical line and horizontal line combine to make a L shape. There is one row of entries
aivan3 [116]

The synthetic division's representation of the dividend is 2x3 + 10x2 + x + 5.

Given that

An L shape is created when two lines intersect vertically and horizontally.

The shape has entries in two rows.

Entries in row 1 are 2, 10, 1, and 5.

Blank, -10, and 0 are the entries in row 2.

A simplified method of dividing a polynomial with another polynomial equation of degree one is known as synthetic division.

On the exterior, to the left of the form, is entry number 5.

The entry stands for the divisor's zero.

If the variable is x, then this entry to the variable is;

2x³+10x²+x+5

The dividend is thus represented by synthetic division as

2x³+10x²+x+5

The Question is incomplete And complete question is given below!!

What dividend is represented by the synthetic division below? A vertical line and horizontal line combine to make a L shape. There are two rows of entries within the shape. Row 1 has entries 2, 10, 1, 5. Row 2 has entries blank, negative 10, 0, negative 5. Entry negative 5 is on the outside to the left of the shape, and a third row of entries is outside and below the shape. Row 3 has entries 2, 0, 1, 0. Negative 10 x squared minus 5 2 x cubed 10 x squared x 5 2 x squared 1 2 x cubed x.

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5 0
1 year ago
Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
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