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katen-ka-za [31]
3 years ago
7

From the sum of 3a^2−ab−2b^2 and 2a^2+5ab−3b^2 subtract a^2−3ab−4b^2

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0
(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) - (a^2-3ab-4b^2)

First we distribute the negative throughout the last polynomial:

(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) + (-a^2+3ab+4b^2)

Combine like terms:

4a^2 + 7ab - b^2
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A particle moves along the x-axis so that its velocity in feet per second at time x, in seconds, is modeled by the quadratic fun
Katyanochek1 [597]

For this case we have the following equation:

y = 2x ^ 2 - 10x + 12

Where, we have the following variables:

x: time in seconds

y: speed in feet per seconds

For the initial velocity, we evaluate x = 0 in the given equation:

y = 2 (0) ^ 2 - 10 (0) + 12\\y = 12

Therefore, the initial speed is 12 feet per second.

Answer:

The particle's initially velocity is 12.

6 0
3 years ago
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
Brums [2.3K]

Answer:

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

p_v =P(t_9>10.349)=1.34x10^{-6}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation      

\bar X=51.6 represent the sample mean

s=1.1 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =48 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:      

Null hypothesis:\mu \geq 48      

Alternative hypothesis:\mu > 48      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

Calculate the P-value      

First we find the degrees of freedom:

df=n-1=10-1=9

Since is a one-side upper test the p value would be:      

p_v =P(t_9>10.349)=1.34x10^{-6}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.        

5 0
3 years ago
Can SOmeone please help me i need to get a good grade on this please!!!!!!
Rudik [331]

Answer:

20 Units

Step-by-step explanation:

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3 0
3 years ago
Identify the dependent and independent variables in each situation.
klemol [59]
A. independent (x) - expenses, dependent (y) - total cost
B. independent (x) - area, dependent (y) - price
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6 0
3 years ago
Read 2 more answers
What are the two solutions of 2x^2 = -X^2 - 5x - 1?
Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1.  Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0.  This is a quadratic equation.  Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13.  Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
4 years ago
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