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katen-ka-za [31]
3 years ago
7

From the sum of 3a^2−ab−2b^2 and 2a^2+5ab−3b^2 subtract a^2−3ab−4b^2

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0
(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) - (a^2-3ab-4b^2)

First we distribute the negative throughout the last polynomial:

(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) + (-a^2+3ab+4b^2)

Combine like terms:

4a^2 + 7ab - b^2
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Answer:

Amount of Niobium-91 initially

= 300/91 =3.2967mol

2040 years = 3 ×680 = 3 half-lives

therefore, amount left = 0.4121mol

mass of Niobium-91 remaining = 0.4121 ×91 =37.5g

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5^4-x^2+x-2 divided by x - 2
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Step-by-step explanation:

5 0
3 years ago
omar will donate up to $500 to charity. the money will be divided between two charities: the city of youth fund and educational
marshall27 [118]

Answer:

Please refer to the attached graph

Step-by-step explanation:

Knowing the following:

X = amount of money donated to the city youth fund

Y = amount of money donated to the educational growth foundation

We can write the statements in form of equations:  

"Will donate up to $500, the money will be divided between two charities"

(a) X + Y = \$ 500

"The amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund"

(b) Y \geq 4X

If we graph both equations we can see the area where both conditions are met (see graph attached)

Where the blue line is (a) and the red line is (b)

Shaded area represent all the possible solutions for the donations, for example:

X=100 and Y=400 or

X=50 and Y=200, etc.

6 0
3 years ago
The age of father is 4nyears.If the age of his daughter is(2n-9)years.find their total age.​
8_murik_8 [283]

Answer:

4n+(2n-9)

4n+2n-9

6n-9 =the total age

6n=9

divide by 6 both sides.

n=9/6

n=1.5 years.

substitute the value of n in the age of the father and the daughter.

Age of father=4×1.5

6years.

Age of Daughter = (2×1.5)-9

3-9

=-6 years

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4 0
3 years ago
Is the function shown in the graph one-to-one?
Cloud [144]

Answer:

  yes

Step-by-step explanation:

The graph is of a function (one output for every input) that also passes the horizontal line test (one input for every output). Hence it is one-to-one.

For a <em>function</em>, the key for it being one-to-one is that it pass the horizontal line test.

3 0
3 years ago
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