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2 years ago

Create an algebraic expression to solve the following problems.

Mathematics

1 answer:

daser333 [38]2 years ago

7 0

Answer:

Step-by-step explanation:

x is the number of GB

f(x) is the cost in dollars

f(x) = 10x

Bill for 6 GB = f(6) = 60

:::::

f(x) = 8x+15

Bill for 8 GB = f(10) = 95

:::::

f(x) = 5x+30

Bill for 2 GB = f(2) = 40

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The letters of the word COMBINE are placed at random in a row. In how many ways can an arrangement occur such that all vowels ar

Oksana_A [137]

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3 years ago

What function equation is represented by the graph?

kupik [55]

the answer would be ...

f(x) = -5/2x + 4

We know this because the constant in this equation, 4, is the y-intercept!

This means that the number without the variable is <u>where the line intersects the y-axis. </u>

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We find ourselves at where the line intercepts the x-axis!

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2 years ago

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aleksley [76]

Answer:

The answer is A

Step-by-step explanation:

240,000 = 60%

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7 0

2 years ago

Read 2 more answers

The side lenghts of a square measures 10x+5. the side lenghts of a triangle are 30x,3x and 6x+30. the square and triangle have t

Goshia [24]

(10x+5)4 = 30x + 3x + 6x +30

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5 0

2 years ago

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

2 years ago