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Allisa [31]
3 years ago
10

A hotel currently has enough room to accommodate at most 200 guests per night. It plans to expand its capacity by 12 guests ever

y year. To make a profit, the hotel must have at least 40 guests staying in the hotel. The hotel manager expects that threshold to increase by 10% every year.
The manager modeled this situation with a system of linear inequalities, where x is the time from today, in years, and y is the number of guests. Which ordered pairs represent viable solutions of this system?
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

(20,280) and (10,300)

Step-by-step explanation:

It was the correct answer on the practice question

ra1l [238]3 years ago
5 0

Answer:

Edmentum/Plato

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Andreyy89

Answer:

Step-by-step explanation:

If you work through it as if you were doing polynomial long division you just have to work through the first step and then compare it to the answer.  In polynomial long division you always divide the leading term of the dividend and divide it by the leading term of the divisor.  In this case 24x^2 /ax = -8x.  So this is a pretty simple calculation to find what a is.  the xs cancel out so you get 24x/a = -8x and from here you can divide both sides by x, multiply both sides by a and then divide both sides by -8.

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Now just follow through with the whole long division to make sure, but using this method should get you the right answer.  

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Step-by-step explanation:

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