3 years ago

8/6 + (− 9 / 5 )

Mathematics

1 answer:

Inessa05 [86]3 years ago

8 0

Answer:

-7/15

Step-by-step explanation:

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$i=\sqrt{-1}\to i^2=-1\ (i-the\ imaginary\ unit)\\----------------------\\\\\frac{8}{7-i}\\\\use\ (a-b)(a+b)=a^2-b^2\\\\\frac{8}{7-i}\cdot\frac{7+i}{7+i}=\frac{56+8i}{7^2-i^2}=\frac{56+8i}{49-(-1)}=\frac{56+8i}{49+1}=\frac{56+8i}{50}=\frac{56}{50}+\frac{8}{50}i\\\\=\boxed{\frac{28}{25}+\frac{4}{25}i}$