Answer:
Cost to construct the road = 775000 rupees
Step-by-step explanation:
Square field has a side = 150 m
Area of the field = (Side)²
= (150)²
= 22500 m²
Length of the park with road around the field = 150 + 2×(width of the road)
= 150 + (2×5)
= 160 m
Similarly, width of the park with road around the field = 160 m
Area of the park with road = (Side)²
= (160)²
= 25600 m²
Area of road = Area of the park with road - Area of the park
= 25600 - 22500
= 3100 m²
Since, cost of constructing the road = 250 rupees per square meter
Cost to construct the road with the given area = 250 × 3100
= 775000 rupees
Answer:
x=4/3 , x=-5/2
Step-by-step explanation:
6x^2 +7x=20
6x^2+7x-20=0
(3x−4)(2x+5)
3x-4=0 , 2x+5=0
3x=4 , 2x=-5
x=4/3 , x=-5/2
I'm pretty sure it's:
A right rectangular prism with length 15 inches, width of 8 inches, and height of 6 inches.
A cross section parallel to the base is a rectangle measuring 15 inches by 8 inches
A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches
Just visualize the rectangle
