Answer:
A dot product of two vectors is also called the scalar product. ... The difference between the dot product and the cross product of two vectors is that the result of the dot product is a scalar quantity, whereas the result of the cross product is a vector quantity.
Explanation:
Hope it is helpful.....
Answer:
twice
Explanation:
From magnification = height of image / height of object
Distance of image/ distance of object = magnification
If the distance and height of the object represents the initial light distance and the exposed surface respectively.
And similarly the distance and height of the image represents the final light distance and the exposed surface respectively.
Hence the new image exposure would be twice as large.
If we use the formula our point of investigation is Height of image,
H2= D2/D1× H1
H2 = 2D2/D1 × H1
H2 = 2H1
Answer:
a) 35 sequndos b) M1 = 600m M2 = 875m
Explanation:
a)
Antes de que el otro móvil comience a moverse, el primer móvil ha viajado 5 segundos a una velocidad de 15 m / s.
5 segundos x 15 m / s = 75 metros.
Podemos establecer una ecuación con la información que conocemos. Juntos, en total, los dos recorren 1475 metros.
Voy a representar el tiempo como t. Un móvil ya ha recorrido 75 metros y hará otros 15 t. El otro aún no se ha movido y viajará 25t. Esos tres números se sumarán a 1475.
75 + 15t + 25t = 1475.
Resta 75 de ambos lados y suma términos similares de t: 40t = 1400
t = 35 segundos.
b)
Ahora tome la distancia recorrida por cada vehículo por separado y conecte 35 segundos para t.
Primer móvil: 75 + 15t = 75 + 15 (35) = 600m
Segundo móvil: 25t = 25 (35) = 875m
Usé un traductor para entender la pregunta y luego traduje lo que escribí. Lo siento si mi explicación no es clara.
Answer:
Part a)
Part b)
Part c)
Part d)
Part e)
Part f)
Explanation:
Part a)
Magnitude of tension force is given as
at 26.9 degree with vertical
Part b)
Net force on Tarzen is given as
Part c)
magnitude of the force is given as
Part d)
Direction of the force is given as
Part e)
Magnitude of the acceleration
tex]a = \frac{384.2}{86.5}[/tex]
Part f)
Direction of acceleration is same as the direction of the force
Answer:Zero
Explanation:
Given child moves the box with constant velocity over his head .
Force acting on box due to gravity is equal to his weight
Displacement of the box is Perpendicular to the direction of Applied force
Work done is given by
here 
is the angle between Force and displacement which is 
so work done is zero
