Answer:
The value is 
The direction is into the surface
Explanation:
From the question we are told that
The mass density is 
The coefficient of kinetic friction is
The current the wire carries is 
Generally the magnetic force acting on the wire is mathematically represented as

Here
is the frictional force which is mathematically represented as

While
is the magnetic force which is mathematically represented as

Here
is the angle between the direction of the force and that of the current
So

So

=> ![B = \mu_k * \frac{m}{L} * [\frac{g}{I} ]](https://tex.z-dn.net/?f=B%20%20%3D%20%20%5Cmu_k%20%2A%20%20%5Cfrac%7Bm%7D%7BL%7D%20%2A%20%5B%5Cfrac%7Bg%7D%7BI%7D%20%5D)
=> ![B = 0.25 * 0.117 * [\frac{9.8}{1.24} ]](https://tex.z-dn.net/?f=B%20%20%3D%20%200.25%20%2A%20%200.117%20%20%2A%20%5B%5Cfrac%7B9.8%7D%7B1.24%7D%20%5D)
=> 
Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image
Answer:
correct answer is C
Explanation:
In this exercise, you are asked to complete the sentences so that the sentence makes sense.
1) in projectile launching, the only force that acts is gravity in the vertical direction, so the time of going up is EQUAL to the time of going down
correct answer C
2) when a body falls freely, the acceleration is the ratio of gravity, therefore if it starts from rest, its height is
y = v₀ t - ½ gt²
v₀ = 0
y = -1/2 g t²
so the position is not proportional to the square of the time
correct answer is C
<span>The plates make up Earth's outer shell, called the lithosphere. (This includes the crust and uppermost part of the mantle.) Churning currents in the molten rocks below propel them along like a jumble of conveyor belts in disrepair. Most geologic activity stems from the interplay where the plates meet or divide.</span>
As per the third law of Newton, the force exerted by the boat over the student is equal in magnitude to the force that the student exerted on the boat.
So, calculate the force on the student using the second law of Newton, Force = mass * acceleration.
Force on the student = 60 kg * 2.0 m/s^2 = 120 N.
=> horizontal force exerted by the student on the boat = 120 N
Answer: option d. 120 N. toward the back of the boat.
Of course it is toward the back because that is where the student jumped from..