What is the difference in graph shape when it is postion vs.time vs. velocity vs. time graph. Using a motion detector.

A good netballer has strong ones

never [62]

I don’t rly get ur question

3 0

3 years ago

The 20 or so minerals that make up most of the rocks of earth's crust are know as what

STALIN [3.7K]

Rock-forming minerals because they formed the earths crust

7 0

3 years ago

What velocity in km/hr would it take to accelerate a 2 kg object to the same momentum of a 1500 kg object with a velocity of 1.6

Lynna [10]

Answer:

v = 4374 Km/h

Explanation:

Given that,

Mass of the smaller object, m = 2 Kg

Mass of the bigger object, M = 1500 Kg

Velocity of the bigger object, V = 1.62 m/s

Velocity of the smaller object, v = ?

The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula

p = mv Kg m/s

To find the momentum of the bigger object, substitute M and V in the above equation

p = 1500 Kg x 1.62 m/s

= 2430 Kg m/s

The velocity imparted to the small body to attain this momentum is given by the relation

v = p/m m/s

= 2430 Kg m/s / 2 Kg

= 1215 m/s

By converting the velocity to Km/h

v = 4374 km/h

Hence, the velocity of the 2 Kg object is v = 4374 km/h

6 0

3 years ago

An alpha particle (Î±), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elec

vaieri [72.5K]

Answer:

Speed = 575 m/s

Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.

Explanation:

Given :

Potential difference, U = $-3.45 \times 10^{-3} \ V$

Mass of the alpha particle, $m_{\alpha} = 6.68 \times 10^{-27} \ kg$

Charge of the alpha particle is, $q_{\alpha} = 3.20 \times 10^{-19} \ C$

So the potential difference for the alpha particle when it is accelerated through the potential difference is

$U=\Delta Vq_{\alpha}$

And the kinetic energy gained by the alpha particle is

$K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2$

From the law of conservation of energy, we get

$K.E. = U$

$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$

$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$

$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$

$v_{\alpha} \approx 575 \ m/s$

The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

-- magnetic forces

-- gravitational forces

5 0

3 years ago

Gold has 118 neutrons. If a gold atom were to lose a neutron, what would happen?

nexus9112 [7]

Answer:

answer is B! if it adds one it becomes platinum and if it loses one it becomes mercury.

6 0

3 years ago