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3 years ago

Anyone wants me to do their math homework for then? I can do do elementary school, middle, and high school math homework

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

I need help can u help?

Stells [14]3 years ago

7 0

Answer:

Step-by-step explanation:

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Find the indicated side of the triangle.<br> Please Help!!!

Angelina_Jolie [31]

Answer:

Step-by-step explanation:

So you can use the special formula for 30-60-90 triangle or you can use the whole Soh Cah Toa thing.

I honestly prefer trig. so a is the opposite side of the 30 deg and 12 is the hyp. This should scream sine to you since sine goes with opposite/hypotenuse.

sin(30 deg)=a/12

Multiply both sides by 12

giving a=12 sin(30)

Type into calculator unless you know your unit circle well.

a=6

6 0

3 years ago

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Help is for my daughter

marysya [2.9K]

Answer:

Step-by-step explanation:

8 0

3 years ago

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IF YOU ARENT ANY OF THES PEOPLE PLZ DON'T ANSWER THIS QUESTION. Hobie, kkmmll44, Katyazamo.

Marianna [84]

The Associative Property say that it doesn't matter how we group the numbers (i.e. which we calculate first) when we add

(a + b) + c = a + (b + c)

The Commutative Property say we can swap numbers over and still get the same answer when we add

a + b = b + a

The Distributive Property:

a(b + c) = ab + ac

------------------------------------------

-3a + 4b + 5a + (-7b) = -3a + 5a + 4b + (-7b)

<h3>Answer: the commutative property</h3>

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3 years ago

Which theorem or postulate proves that △ABC and △DEF are similar?

yan [13]

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

$\frac{ED}{AB}= \frac{7}{21}$

$\frac{ED}{AB}= \frac{1}{3}$

and

$\frac{EF}{BC}= \frac{11}{33}$

$\frac{EF}{BC}= \frac{1}{3}$

Thus

$\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}$

∠ABC = ∠DEF (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

7 0

3 years ago

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Make g the subject of this relation

zhannawk [14.2K]

Answer:

see explanation

Step-by-step explanation:

Simplify the radical

$\frac{U}{\frac{1}{f}+\frac{1}{g} }$

= $\frac{U}{\frac{g+f}{fg} }$

= $\frac{Ufg}{g+f}$

Square both sides

T² = $\frac{Ufg}{g+f}$ ( multiply both sides by (g + f) )

T²(g + f) = Ufg ( distribute left side )

T²g + T²f = Ufg ← subtract Ufg from both sides

T²g - Ufg + T²f = 0 ← subtract T²f from both sides

T²g - Ufg = - T²f ← factor out g from each term on the left side

g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)

g = - $\frac{T^2f}{T^2-Uf}$ = $\frac{T^2f}{Uf-T^2}$

6 0

3 years ago